The sum of 6 consecutive odd numbers exceeds twice the largest by 38. Find the sum of the six numbers ?
Created: 6 years ago |
Updated: 2 years ago
best des
Let x represent the smallest number. Then the other number are x + 2, x + 4, x + 6, x + 8 and x + 10. x + 10 is the largest.
The sum of these is 6x + (2 + 4 + 6 + 8 + 10) = 6x + 30
We are told that this is 38 greater than twice the largest, so
6x + 30 = 2(x + 10) + 38 = 2x + 58.
or, 4x = 28
∴x = 7
Then the sum is 6×7 + 30 = 72.
Md Azizur Rahman
Founder of Satt
Related Question
View More
Created: 6 years ago |
Updated: 9 months ago
Created: 6 years ago |
Updated: 9 months ago
Created: 6 years ago |
Updated: 3 months ago
Promotion
Download Our Mobile Apps
